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31144443113 = 74449206159
BaseRepresentation
bin11101000000010110…
…100111110011101001
32222101111202122012002
4131000112213303221
51002240434134423
622150233300345
72151534253460
oct350026476351
988344678162
1031144443113
1112232254093
1260522646b5
132c24506a84
1417164359d7
15c2433d228
hex7405a7ce9

31144443113 has 4 divisors (see below), whose sum is σ = 35593649280. Its totient is φ = 26695236948.

The previous prime is 31144443097. The next prime is 31144443137. The reversal of 31144443113 is 31134444113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31134444113 = 171831437889.

It is a cyclic number.

It is not a de Polignac number, because 31144443113 - 24 = 31144443097 is a prime.

It is not an unprimeable number, because it can be changed into a prime (31144443013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2224603073 + ... + 2224603086.

It is an arithmetic number, because the mean of its divisors is an integer number (8898412320).

Almost surely, 231144443113 is an apocalyptic number.

It is an amenable number.

31144443113 is a deficient number, since it is larger than the sum of its proper divisors (4449206167).

31144443113 is an equidigital number, since it uses as much as digits as its factorization.

31144443113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4449206166.

The product of its digits is 6912, while the sum is 29.

Adding to 31144443113 its reverse (31134444113), we get a palindrome (62278887226).

The spelling of 31144443113 in words is "thirty-one billion, one hundred forty-four million, four hundred forty-three thousand, one hundred thirteen".

Divisors: 1 7 4449206159 31144443113