31144504135041 has 48 divisors (see below), whose sum is σ = 50660450500608. Its totient is φ = 18266153320800.

The previous prime is 31144504135001. The next prime is 31144504135061. The reversal of 31144504135041 is 14053140544113.

31144504135041 is a `hidden beast` number, since 3 + 1 + 14 + 4 + 504 + 135 + 0 + 4 + 1 = 666.

It is not a de Polignac number, because 31144504135041 - 2¹⁵ = 31144504102273 is a prime.

It is a super-3 number, since 3×31144504135041³ (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31144504134987 and 31144504135005.

It is not an unprimeable number, because it can be changed into a prime (31144504135001) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 179041390 + ... + 179215256.

It is an arithmetic number, because the mean of its divisors is an integer number (1055426052096).

Almost surely, 2^{31144504135041} is an apocalyptic number.

31144504135041 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

It is an amenable number.

31144504135041 is a deficient number, since it is larger than the sum of its proper divisors (19515946365567).

31144504135041 is a wasteful number, since it uses less digits than its factorization.

31144504135041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 232282 (or 232279 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 36.

Adding to 31144504135041 its reverse (14053140544113), we get a palindrome (45197644679154).

The spelling of 31144504135041 in words is "thirty-one trillion, one hundred forty-four billion, five hundred four million, one hundred thirty-five thousand, forty-one".