31145211254113 has 4 divisors (see below), whose sum is σ = 33976594095408. Its totient is φ = 28313828412820.

The previous prime is 31145211254083. The next prime is 31145211254117.

31145211254113 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31145211254113 - 2²¹ = 31145209156961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31145211254117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1415691420631 + ... + 1415691420652.

It is an arithmetic number, because the mean of its divisors is an integer number (8494148523852).

Almost surely, 2^{31145211254113} is an apocalyptic number.

It is an amenable number.

31145211254113 is a deficient number, since it is larger than the sum of its proper divisors (2831382841295).

31145211254113 is a wasteful number, since it uses less digits than its factorization.

31145211254113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2831382841294.

The product of its digits is 14400, while the sum is 34.

It can be divided in two parts, 3114521 and 1254113, that added together give a palindrome (4368634).

The spelling of 31145211254113 in words is "thirty-one trillion, one hundred forty-five billion, two hundred eleven million, two hundred fifty-four thousand, one hundred thirteen".