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31145343000103 = 49411630332173
BaseRepresentation
bin1110001010011100101110…
…00110110001111000100111
311002021110120111121120222001
413011032113012301320213
513040241130302000403
6150123550102350131
76363114430303303
oct705162706617047
9132243514546861
1031145343000103
119a18736191152
1235b021442b347
13144bcbb2006a7
1479962a88ad03
1539026636cc1d
hex1c53971b1e27

31145343000103 has 4 divisors (see below), whose sum is σ = 31145973381688. Its totient is φ = 31144712618520.

The previous prime is 31145343000043. The next prime is 31145343000193. The reversal of 31145343000103 is 30100034354113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31145343000103 - 217 = 31145342869031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31145343000193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 315116676 + ... + 315215497.

It is an arithmetic number, because the mean of its divisors is an integer number (7786493345422).

Almost surely, 231145343000103 is an apocalyptic number.

31145343000103 is a deficient number, since it is larger than the sum of its proper divisors (630381585).

31145343000103 is an equidigital number, since it uses as much as digits as its factorization.

31145343000103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 630381584.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 31145343000103 its reverse (30100034354113), we get a palindrome (61245377354216).

The spelling of 31145343000103 in words is "thirty-one trillion, one hundred forty-five billion, three hundred forty-three million, one hundred three", and thus it is an aban number.

Divisors: 1 49411 630332173 31145343000103