31146695118053 has 4 divisors (see below), whose sum is σ = 31218961232448. Its totient is φ = 31074429003660.

The previous prime is 31146695118013. The next prime is 31146695118101. The reversal of 31146695118053 is 35081159664113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31146695118053 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31146695117986 and 31146695118004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31146695118013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36133056551 + ... + 36133057412.

It is an arithmetic number, because the mean of its divisors is an integer number (7804740308112).

Almost surely, 2^{31146695118053} is an apocalyptic number.

It is an amenable number.

31146695118053 is a deficient number, since it is larger than the sum of its proper divisors (72266114395).

31146695118053 is an equidigital number, since it uses as much as digits as its factorization.

31146695118053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72266114394.

The product of its (nonzero) digits is 2332800, while the sum is 53.

The spelling of 31146695118053 in words is "thirty-one trillion, one hundred forty-six billion, six hundred ninety-five million, one hundred eighteen thousand, fifty-three".