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31150341324721 is a prime number
BaseRepresentation
bin1110001010100110000010…
…00001110111111110110001
311002021221110211211210100001
413011103001001313332301
513040331344334342341
6150130134054030001
76363352332332263
oct705230101677661
9132257424753301
1031150341324721
119a1a870654443
1235b118a348301
13144c6068c3818
14799982633b33
1539045a092d31
hex1c54c1077fb1

31150341324721 has 2 divisors, whose sum is σ = 31150341324722. Its totient is φ = 31150341324720.

The previous prime is 31150341324677. The next prime is 31150341324727. The reversal of 31150341324721 is 12742314305113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31084862144400 + 65479180321 = 5575380^2 + 255889^2 .

It is a cyclic number.

It is not a de Polignac number, because 31150341324721 - 27 = 31150341324593 is a prime.

It is not a weakly prime, because it can be changed into another prime (31150341324727) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15575170662360 + 15575170662361.

It is an arithmetic number, because the mean of its divisors is an integer number (15575170662361).

Almost surely, 231150341324721 is an apocalyptic number.

It is an amenable number.

31150341324721 is a deficient number, since it is larger than the sum of its proper divisors (1).

31150341324721 is an equidigital number, since it uses as much as digits as its factorization.

31150341324721 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 37.

Adding to 31150341324721 its reverse (12742314305113), we get a palindrome (43892655629834).

The spelling of 31150341324721 in words is "thirty-one trillion, one hundred fifty billion, three hundred forty-one million, three hundred twenty-four thousand, seven hundred twenty-one".