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31150421201213 is a prime number
BaseRepresentation
bin1110001010100110001011…
…10010100101000100111101
311002021221200102010221021122
413011103011302211010331
513040332030311414323
6150130150030040325
76363354322302326
oct705230562450475
9132257612127248
1031150421201213
119a1a901750876
1235b11b10490a5
13144c61a30c912
1479998d0a744d
153904620beec8
hex1c54c5ca513d

31150421201213 has 2 divisors, whose sum is σ = 31150421201214. Its totient is φ = 31150421201212.

The previous prime is 31150421201183. The next prime is 31150421201219. The reversal of 31150421201213 is 31210212405113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 26629707518404 + 4520713682809 = 5160398^2 + 2126197^2 .

It is a cyclic number.

It is not a de Polignac number, because 31150421201213 - 214 = 31150421184829 is a prime.

It is a super-3 number, since 3×311504212012133 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31150421201219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15575210600606 + 15575210600607.

It is an arithmetic number, because the mean of its divisors is an integer number (15575210600607).

Almost surely, 231150421201213 is an apocalyptic number.

It is an amenable number.

31150421201213 is a deficient number, since it is larger than the sum of its proper divisors (1).

31150421201213 is an equidigital number, since it uses as much as digits as its factorization.

31150421201213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 31150421201213 its reverse (31210212405113), we get a palindrome (62360633606326).

The spelling of 31150421201213 in words is "thirty-one trillion, one hundred fifty billion, four hundred twenty-one million, two hundred one thousand, two hundred thirteen".