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31150450241051 is a prime number
BaseRepresentation
bin1110001010100110001111…
…00001010110111000011011
311002021221202102210022110012
413011103013201112320123
513040332110230203201
6150130152544312135
76363355124161511
oct705230741267033
9132257672708405
1031150450241051
119a1a917085939
1235b11ba91264b
13144c62333985b
14799992ca64b1
153904649095bb
hex1c54c7856e1b

31150450241051 has 2 divisors, whose sum is σ = 31150450241052. Its totient is φ = 31150450241050.

The previous prime is 31150450241017. The next prime is 31150450241077. The reversal of 31150450241051 is 15014205405113.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 31150450241051 - 210 = 31150450240027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31150450240999 and 31150450241017.

It is not a weakly prime, because it can be changed into another prime (31150450241551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15575225120525 + 15575225120526.

It is an arithmetic number, because the mean of its divisors is an integer number (15575225120526).

Almost surely, 231150450241051 is an apocalyptic number.

31150450241051 is a deficient number, since it is larger than the sum of its proper divisors (1).

31150450241051 is an equidigital number, since it uses as much as digits as its factorization.

31150450241051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 32.

Adding to 31150450241051 its reverse (15014205405113), we get a palindrome (46164655646164).

The spelling of 31150450241051 in words is "thirty-one trillion, one hundred fifty billion, four hundred fifty million, two hundred forty-one thousand, fifty-one".