Base | Representation |
---|---|
bin | 1001000100010001010… |
… | …01001001101010000111 |
3 | 1002210010001220112022201 |
4 | 10202020221021222013 |
5 | 20101003203243101 |
6 | 355040455535331 |
7 | 31336002306655 |
oct | 4421051115207 |
9 | 1083101815281 |
10 | 311530134151 |
11 | 110134703795 |
12 | 5046298a547 |
13 | 234b982c3b2 |
14 | 111145addd5 |
15 | 8184a69e01 |
hex | 4888a49a87 |
311530134151 has 4 divisors (see below), whose sum is σ = 322272552600. Its totient is φ = 300787715704.
The previous prime is 311530134107. The next prime is 311530134173. The reversal of 311530134151 is 151431035113.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 151431035113 = 2371 ⋅63868003.
It is a cyclic number.
It is not a de Polignac number, because 311530134151 - 27 = 311530134023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311530135151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5371209181 + ... + 5371209238.
It is an arithmetic number, because the mean of its divisors is an integer number (80568138150).
Almost surely, 2311530134151 is an apocalyptic number.
311530134151 is a deficient number, since it is larger than the sum of its proper divisors (10742418449).
311530134151 is a wasteful number, since it uses less digits than its factorization.
311530134151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10742418448.
The product of its (nonzero) digits is 2700, while the sum is 28.
Adding to 311530134151 its reverse (151431035113), we get a palindrome (462961169264).
The spelling of 311530134151 in words is "three hundred eleven billion, five hundred thirty million, one hundred thirty-four thousand, one hundred fifty-one".
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