311541135001 has 2 divisors, whose sum is σ = 311541135002. Its totient is φ = 311541135000.

The previous prime is 311541134977. The next prime is 311541135047. The reversal of 311541135001 is 100531145113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 296426891401 + 15114243600 = 544451^2 + 122940^2 .

It is a cyclic number.

It is not a de Polignac number, because 311541135001 - 2¹⁵ = 311541102233 is a prime.

It is a super-2 number, since 2×311541135001² (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (311541195001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155770567500 + 155770567501.

It is an arithmetic number, because the mean of its divisors is an integer number (155770567501).

Almost surely, 2^311541135001 is an apocalyptic number.

It is an amenable number.

311541135001 is a deficient number, since it is larger than the sum of its proper divisors (1).

311541135001 is an equidigital number, since it uses as much as digits as its factorization.

311541135001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 25.

The spelling of 311541135001 in words is "three hundred eleven billion, five hundred forty-one million, one hundred thirty-five thousand, one".