Base | Representation |
---|---|
bin | 101101010101011101110… |
… | …111100001011100110111 |
3 | 102000211110101212222211212 |
4 | 231111131313201130313 |
5 | 402020343042004443 |
6 | 10343112413552035 |
7 | 441040110064550 |
oct | 55253567413467 |
9 | 12024411788755 |
10 | 3115426125623 |
11 | aa1276913329 |
12 | 423959aa561b |
13 | 197a25246616 |
14 | aab049c3327 |
15 | 5608cdb7618 |
hex | 2d55dde1737 |
3115426125623 has 4 divisors (see below), whose sum is σ = 3560487000720. Its totient is φ = 2670365250528.
The previous prime is 3115426125601. The next prime is 3115426125629. The reversal of 3115426125623 is 3265216245113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3115426125623 - 232 = 3111131158327 is a prime.
It is a super-3 number, since 3×31154261256233 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3115426125629) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222530437538 + ... + 222530437551.
It is an arithmetic number, because the mean of its divisors is an integer number (890121750180).
Almost surely, 23115426125623 is an apocalyptic number.
3115426125623 is a deficient number, since it is larger than the sum of its proper divisors (445060875097).
3115426125623 is an equidigital number, since it uses as much as digits as its factorization.
3115426125623 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 445060875096.
The product of its digits is 259200, while the sum is 41.
The spelling of 3115426125623 in words is "three trillion, one hundred fifteen billion, four hundred twenty-six million, one hundred twenty-five thousand, six hundred twenty-three".
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