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31157075113 = 54075762359
BaseRepresentation
bin11101000001000110…
…110011110010101001
32222102101112102000221
4131001012303302221
51002302202400423
622151404130041
72152046524453
oct350106636251
988371472027
1031157075113
11122393a175a
126056536921
132c2700a628
141717da32d3
15c254d5e5d
hex7411b3ca9

31157075113 has 4 divisors (see below), whose sum is σ = 31162842880. Its totient is φ = 31151307348.

The previous prime is 31157075087. The next prime is 31157075137.

31157075113 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31157075113 - 221 = 31154977961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31157075413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2875773 + ... + 2886586.

It is an arithmetic number, because the mean of its divisors is an integer number (7790710720).

Almost surely, 231157075113 is an apocalyptic number.

It is an amenable number.

31157075113 is a deficient number, since it is larger than the sum of its proper divisors (5767767).

31157075113 is an equidigital number, since it uses as much as digits as its factorization.

31157075113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5767766.

The product of its (nonzero) digits is 11025, while the sum is 34.

It can be divided in two parts, 311570 and 75113, that added together give a palindrome (386683).

The spelling of 31157075113 in words is "thirty-one billion, one hundred fifty-seven million, seventy-five thousand, one hundred thirteen".

Divisors: 1 5407 5762359 31157075113