Base | Representation |
---|---|
bin | 101101010110000110010… |
… | …110110011111100111111 |
3 | 102000220012202002112202122 |
4 | 231112012112303330333 |
5 | 402023240441312021 |
6 | 10343304041313155 |
7 | 441062666004503 |
oct | 55260626637477 |
9 | 12026182075678 |
10 | 3116105416511 |
11 | aa15952a865a |
12 | 423b094957bb |
13 | 197b02bb48a9 |
14 | aab6acca303 |
15 | 560cc848bab |
hex | 2d5865b3f3f |
3116105416511 has 2 divisors, whose sum is σ = 3116105416512. Its totient is φ = 3116105416510.
The previous prime is 3116105416399. The next prime is 3116105416547. The reversal of 3116105416511 is 1156145016113.
It is a strong prime.
It is an emirp because it is prime and its reverse (1156145016113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3116105416511 - 234 = 3098925547327 is a prime.
It is a super-2 number, since 2×31161054165112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3116155416511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1558052708255 + 1558052708256.
It is an arithmetic number, because the mean of its divisors is an integer number (1558052708256).
Almost surely, 23116105416511 is an apocalyptic number.
3116105416511 is a deficient number, since it is larger than the sum of its proper divisors (1).
3116105416511 is an equidigital number, since it uses as much as digits as its factorization.
3116105416511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 35.
The spelling of 3116105416511 in words is "three trillion, one hundred sixteen billion, one hundred five million, four hundred sixteen thousand, five hundred eleven".
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