Base | Representation |
---|---|
bin | 11101000011100111… |
… | …010001100000001000 |
3 | 2222112022200112000002 |
4 | 131003213101200020 |
5 | 1002343434433343 |
6 | 22155505502132 |
7 | 2153100212252 |
oct | 350347214010 |
9 | 88468615002 |
10 | 31199139848 |
11 | 122601125a8 |
12 | 6068641948 |
13 | 2c32947bc6 |
14 | 171d7d2cd2 |
15 | c290448b8 |
hex | 7439d1808 |
31199139848 has 64 divisors (see below), whose sum is σ = 62826192000. Its totient is φ = 14479575552.
The previous prime is 31199139847. The next prime is 31199139887. The reversal of 31199139848 is 84893199113.
It is a super-2 number, since 2×311991398482 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31199139793 and 31199139802.
It is not an unprimeable number, because it can be changed into a prime (31199139847) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6901733 + ... + 6906251.
It is an arithmetic number, because the mean of its divisors is an integer number (981659250).
Almost surely, 231199139848 is an apocalyptic number.
31199139848 is a gapful number since it is divisible by the number (38) formed by its first and last digit.
It is an amenable number.
31199139848 is an abundant number, since it is smaller than the sum of its proper divisors (31627052152).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31199139848 is a wasteful number, since it uses less digits than its factorization.
31199139848 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5454 (or 5450 counting only the distinct ones).
The product of its digits is 1679616, while the sum is 56.
The spelling of 31199139848 in words is "thirty-one billion, one hundred ninety-nine million, one hundred thirty-nine thousand, eight hundred forty-eight".
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