Base | Representation |
---|---|
bin | 100011011110000110010111… |
… | …1101111110000010011011111 |
3 | 1111220200220211010122002110201 |
4 | 1012330030233233300103133 |
5 | 311343302211221043403 |
6 | 3023322512203044331 |
7 | 122501156405343445 |
oct | 10674145757602337 |
9 | 1456626733562421 |
10 | 312000110331103 |
11 | 9045a55a501757 |
12 | 2abab8658106a7 |
13 | 1051263a91467c |
14 | 5708c58d34b95 |
15 | 2610c8b2c521d |
hex | 11bc32fbf04df |
312000110331103 has 2 divisors, whose sum is σ = 312000110331104. Its totient is φ = 312000110331102.
The previous prime is 312000110331079. The next prime is 312000110331149. The reversal of 312000110331103 is 301133011000213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312000110331103 - 233 = 311991520396511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312000110331703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156000055165551 + 156000055165552.
It is an arithmetic number, because the mean of its divisors is an integer number (156000055165552).
Almost surely, 2312000110331103 is an apocalyptic number.
312000110331103 is a deficient number, since it is larger than the sum of its proper divisors (1).
312000110331103 is an equidigital number, since it uses as much as digits as its factorization.
312000110331103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 312000110331103 its reverse (301133011000213), we get a palindrome (613133121331316).
The spelling of 312000110331103 in words is "three hundred twelve trillion, one hundred ten million, three hundred thirty-one thousand, one hundred three".
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