Base | Representation |
---|---|
bin | 100011011110000110011000… |
… | …0011100010011111100010011 |
3 | 1111220200220211221121111211201 |
4 | 1012330030300130103330103 |
5 | 311343302222213331121 |
6 | 3023322513301252031 |
7 | 122501156606542021 |
oct | 10674146034237423 |
9 | 1456626757544751 |
10 | 312000122011411 |
11 | 9045a56605a2a9 |
12 | 2abab869704017 |
13 | 10512640173cb2 |
14 | 5708c5a6d5711 |
15 | 2610c8c330e91 |
hex | 11bc330713f13 |
312000122011411 has 2 divisors, whose sum is σ = 312000122011412. Its totient is φ = 312000122011410.
The previous prime is 312000122011399. The next prime is 312000122011423. The reversal of 312000122011411 is 114110221000213.
It is a balanced prime because it is at equal distance from previous prime (312000122011399) and next prime (312000122011423).
It is a cyclic number.
It is not a de Polignac number, because 312000122011411 - 25 = 312000122011379 is a prime.
It is a super-2 number, since 2×3120001220114112 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (312000122011471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156000061005705 + 156000061005706.
It is an arithmetic number, because the mean of its divisors is an integer number (156000061005706).
Almost surely, 2312000122011411 is an apocalyptic number.
312000122011411 is a deficient number, since it is larger than the sum of its proper divisors (1).
312000122011411 is an equidigital number, since it uses as much as digits as its factorization.
312000122011411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 312000122011411 its reverse (114110221000213), we get a palindrome (426110343011624).
The spelling of 312000122011411 in words is "three hundred twelve trillion, one hundred twenty-two million, eleven thousand, four hundred eleven".
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