Base | Representation |
---|---|
bin | 100011011110000110011000… |
… | …1001111111000110000011111 |
3 | 1111220200220212220001101222122 |
4 | 1012330030301033320300133 |
5 | 311343302234144002201 |
6 | 3023322514503133155 |
7 | 122501160132502235 |
oct | 10674146117706037 |
9 | 1456626786041878 |
10 | 312000135531551 |
11 | 9045a572754175 |
12 | 2abab8721441bb |
13 | 10512642bc8b8c |
14 | 5708c5c414955 |
15 | 2610c8d601e1b |
hex | 11bc3313f8c1f |
312000135531551 has 4 divisors (see below), whose sum is σ = 312000288484632. Its totient is φ = 311999982578472.
The previous prime is 312000135531547. The next prime is 312000135531559. The reversal of 312000135531551 is 155135531000213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 312000135531551 - 22 = 312000135531547 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312000135531559) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73374845 + ... + 77510438.
It is an arithmetic number, because the mean of its divisors is an integer number (78000072121158).
Almost surely, 2312000135531551 is an apocalyptic number.
312000135531551 is a deficient number, since it is larger than the sum of its proper divisors (152953081).
312000135531551 is a wasteful number, since it uses less digits than its factorization.
312000135531551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 152953080.
The product of its (nonzero) digits is 33750, while the sum is 35.
Adding to 312000135531551 its reverse (155135531000213), we get a palindrome (467135666531764).
The spelling of 312000135531551 in words is "three hundred twelve trillion, one hundred thirty-five million, five hundred thirty-one thousand, five hundred fifty-one".
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