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312000334000423 = 816398338216681
BaseRepresentation
bin100011011110000110011110…
…1000100111111000100100111
31111220200221101201111200002121
41012330030331010333010213
5311343303141001003143
63023322550313050411
7122501165062451545
oct10674147504770447
91456627351450077
10312000334000423
119045a664790832
122abab9086b6a07
1310512675068293
145708c7a918d95
152610ca0c577ed
hex11bc33d13f127

312000334000423 has 4 divisors (see below), whose sum is σ = 312000380381088. Its totient is φ = 312000287619760.

The previous prime is 312000334000373. The next prime is 312000334000489. The reversal of 312000334000423 is 324000433000213.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 312000334000423 - 217 = 312000333869351 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312000334010423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10944358 + ... + 27272323.

It is an arithmetic number, because the mean of its divisors is an integer number (78000095095272).

Almost surely, 2312000334000423 is an apocalyptic number.

312000334000423 is a deficient number, since it is larger than the sum of its proper divisors (46380665).

312000334000423 is an equidigital number, since it uses as much as digits as its factorization.

312000334000423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46380664.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 312000334000423 its reverse (324000433000213), we get a palindrome (636000767000636).

The spelling of 312000334000423 in words is "three hundred twelve trillion, three hundred thirty-four million, four hundred twenty-three", and thus it is an aban number.

Divisors: 1 8163983 38216681 312000334000423