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312001024481 is a prime number
BaseRepresentation
bin1001000101001001011…
…01011101000111100001
31002211022212222020102022
410202210231131013201
520102434230240411
6355155320431225
731353450644036
oct4424455350741
91084285866368
10312001024481
11110356498653
1250574618515
1323563261823
141115ad4938d
1581b1082edb
hex48a4b5d1e1

312001024481 has 2 divisors, whose sum is σ = 312001024482. Its totient is φ = 312001024480.

The previous prime is 312001024399. The next prime is 312001024483. The reversal of 312001024481 is 184420100213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 262164480400 + 49836544081 = 512020^2 + 223241^2 .

It is a cyclic number.

It is not a de Polignac number, because 312001024481 - 230 = 310927282657 is a prime.

It is a super-2 number, since 2×3120010244812 (a number of 24 digits) contains 22 as substring.

Together with 312001024483, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 312001024481.

It is not a weakly prime, because it can be changed into another prime (312001024483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156000512240 + 156000512241.

It is an arithmetic number, because the mean of its divisors is an integer number (156000512241).

Almost surely, 2312001024481 is an apocalyptic number.

It is an amenable number.

312001024481 is a deficient number, since it is larger than the sum of its proper divisors (1).

312001024481 is an equidigital number, since it uses as much as digits as its factorization.

312001024481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 312001024481 its reverse (184420100213), we get a palindrome (496421124694).

The spelling of 312001024481 in words is "three hundred twelve billion, one million, twenty-four thousand, four hundred eighty-one".