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3120011010133 is a prime number
BaseRepresentation
bin101101011001101111001…
…001011110000001010101
3102001021021221011021000021
4231121233021132001111
5402104240304311013
610345151355545141
7441261532004023
oct55315711360125
912037257137007
103120011010133
11aa3209970986
1242481945b1b1
131982a60a0834
14ab01b8a7713
155625a671a8d
hex2d66f25e055

3120011010133 has 2 divisors, whose sum is σ = 3120011010134. Its totient is φ = 3120011010132.

The previous prime is 3120011009993. The next prime is 3120011010139. The reversal of 3120011010133 is 3310101100213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3071543666724 + 48467343409 = 1752582^2 + 220153^2 .

It is an emirp because it is prime and its reverse (3310101100213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3120011010133 - 213 = 3120011001941 is a prime.

It is a super-2 number, since 2×31200110101332 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3120011010139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560005505066 + 1560005505067.

It is an arithmetic number, because the mean of its divisors is an integer number (1560005505067).

Almost surely, 23120011010133 is an apocalyptic number.

It is an amenable number.

3120011010133 is a deficient number, since it is larger than the sum of its proper divisors (1).

3120011010133 is an equidigital number, since it uses as much as digits as its factorization.

3120011010133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 3120011010133 its reverse (3310101100213), we get a palindrome (6430112110346).

The spelling of 3120011010133 in words is "three trillion, one hundred twenty billion, eleven million, ten thousand, one hundred thirty-three".