312001140432301 has 4 divisors (see below), whose sum is σ = 322065693349504. Its totient is φ = 301936587515100.

The previous prime is 312001140432277. The next prime is 312001140432349. The reversal of 312001140432301 is 103234041100213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 312001140432301 - 2¹³ = 312001140424109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312001140432391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5032276458555 + ... + 5032276458616.

It is an arithmetic number, because the mean of its divisors is an integer number (80516423337376).

Almost surely, 2^{312001140432301} is an apocalyptic number.

312001140432301 is a gapful number since it is divisible by the number (31) formed by its first and last digit.

It is an amenable number.

312001140432301 is a deficient number, since it is larger than the sum of its proper divisors (10064552917203).

312001140432301 is a wasteful number, since it uses less digits than its factorization.

312001140432301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10064552917202.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 312001140432301 its reverse (103234041100213), we get a palindrome (415235181532514).

The spelling of 312001140432301 in words is "three hundred twelve trillion, one billion, one hundred forty million, four hundred thirty-two thousand, three hundred one".