Base | Representation |
---|---|
bin | 100011011110000110110110… |
… | …1001100010111100110110101 |
3 | 1111220201000110222110210202122 |
4 | 1012330031231030113212311 |
5 | 311343311314124223133 |
6 | 3023323202351045325 |
7 | 122501224064056436 |
oct | 10674155514274665 |
9 | 1456630428423678 |
10 | 312001141242293 |
11 | 9045aa39418578 |
12 | 2ababab2b10845 |
13 | 105127733854a9 |
14 | 5708d15c0b48d |
15 | 2610ceba60498 |
hex | 11bc36d3179b5 |
312001141242293 has 2 divisors, whose sum is σ = 312001141242294. Its totient is φ = 312001141242292.
The previous prime is 312001141242187. The next prime is 312001141242379. The reversal of 312001141242293 is 392242141100213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 285280274818564 + 26720866423729 = 16890242^2 + 5169223^2 .
It is a cyclic number.
It is not a de Polignac number, because 312001141242293 - 222 = 312001137047989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312001141242893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156000570621146 + 156000570621147.
It is an arithmetic number, because the mean of its divisors is an integer number (156000570621147).
Almost surely, 2312001141242293 is an apocalyptic number.
It is an amenable number.
312001141242293 is a deficient number, since it is larger than the sum of its proper divisors (1).
312001141242293 is an equidigital number, since it uses as much as digits as its factorization.
312001141242293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20736, while the sum is 35.
The spelling of 312001141242293 in words is "three hundred twelve trillion, one billion, one hundred forty-one million, two hundred forty-two thousand, two hundred ninety-three".
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