Base | Representation |
---|---|
bin | 101101011001101111110… |
… | …100001101000110001001 |
3 | 102001021022201020102110022 |
4 | 231121233310031012021 |
5 | 402104301141304001 |
6 | 10345152440030225 |
7 | 441262026143321 |
oct | 55315764150611 |
9 | 12037281212408 |
10 | 3120022213001 |
11 | aa3215222851 |
12 | 424821162375 |
13 | 1982a84c3a55 |
14 | ab01d182281 |
15 | 5625b63611b |
hex | 2d66fd0d189 |
3120022213001 has 4 divisors (see below), whose sum is σ = 3163966187904. Its totient is φ = 3076078238100.
The previous prime is 3120022212997. The next prime is 3120022213013. The reversal of 3120022213001 is 1003122200213.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3120022213001 - 22 = 3120022212997 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3120022213051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21971987345 + ... + 21971987486.
It is an arithmetic number, because the mean of its divisors is an integer number (790991546976).
Almost surely, 23120022213001 is an apocalyptic number.
It is an amenable number.
3120022213001 is a deficient number, since it is larger than the sum of its proper divisors (43943974903).
3120022213001 is an equidigital number, since it uses as much as digits as its factorization.
3120022213001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43943974902.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 3120022213001 its reverse (1003122200213), we get a palindrome (4123144413214).
The spelling of 3120022213001 in words is "three trillion, one hundred twenty billion, twenty-two million, two hundred thirteen thousand, one".
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