312002344231 has 4 divisors (see below), whose sum is σ = 312003461464. Its totient is φ = 312001227000.

The previous prime is 312002344229. The next prime is 312002344237. The reversal of 312002344231 is 132443200213.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 132443200213 = 77491 ⋅1709143.

It is a cyclic number.

It is not a de Polignac number, because 312002344231 - 2¹ = 312002344229 is a prime.

It is a super-3 number, since 3×312002344231³ (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 312002344196 and 312002344205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312002344237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 268756 + ... + 834406.

It is an arithmetic number, because the mean of its divisors is an integer number (78000865366).

Almost surely, 2^312002344231 is an apocalyptic number.

312002344231 is a deficient number, since it is larger than the sum of its proper divisors (1117233).

312002344231 is an equidigital number, since it uses as much as digits as its factorization.

312002344231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1117232.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 312002344231 its reverse (132443200213), we get a palindrome (444445544444).

The spelling of 312002344231 in words is "three hundred twelve billion, two million, three hundred forty-four thousand, two hundred thirty-one".