Base | Representation |
---|---|
bin | 11101000011101100… |
… | …001010110011001001 |
3 | 2222112102002201022102 |
4 | 131003230022303021 |
5 | 1002344302014423 |
6 | 22155553203145 |
7 | 2153114135456 |
oct | 350354126311 |
9 | 88472081272 |
10 | 31200423113 |
11 | 12260909752 |
12 | 6068b604b5 |
13 | 2c32ca7032 |
14 | 171da4882d |
15 | c291e9c28 |
hex | 743b0acc9 |
31200423113 has 2 divisors, whose sum is σ = 31200423114. Its totient is φ = 31200423112.
The previous prime is 31200423097. The next prime is 31200423143. The reversal of 31200423113 is 31132400213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 17848158409 + 13352264704 = 133597^2 + 115552^2 .
It is a cyclic number.
It is not a de Polignac number, because 31200423113 - 24 = 31200423097 is a prime.
It is a super-2 number, since 2×312004231132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31200423143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15600211556 + 15600211557.
It is an arithmetic number, because the mean of its divisors is an integer number (15600211557).
Almost surely, 231200423113 is an apocalyptic number.
It is an amenable number.
31200423113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31200423113 is an equidigital number, since it uses as much as digits as its factorization.
31200423113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 31200423113 its reverse (31132400213), we get a palindrome (62332823326).
The spelling of 31200423113 in words is "thirty-one billion, two hundred million, four hundred twenty-three thousand, one hundred thirteen".
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