Base | Representation |
---|---|
bin | 1001000101001010100… |
… | …00000100110110100011 |
3 | 1002211100112001022212111 |
4 | 10202211100010312203 |
5 | 20102444041201011 |
6 | 355200243140151 |
7 | 31353621043462 |
oct | 4424520046643 |
9 | 1084315038774 |
10 | 312010100131 |
11 | 110360627294 |
12 | 50577674657 |
13 | 235650bb732 |
14 | 1115c22c9d9 |
15 | 81b1c77121 |
hex | 48a5404da3 |
312010100131 has 2 divisors, whose sum is σ = 312010100132. Its totient is φ = 312010100130.
The previous prime is 312010100093. The next prime is 312010100141. The reversal of 312010100131 is 131001010213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312010100131 is a prime.
It is a super-2 number, since 2×3120101001312 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (312010100141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156005050065 + 156005050066.
It is an arithmetic number, because the mean of its divisors is an integer number (156005050066).
Almost surely, 2312010100131 is an apocalyptic number.
312010100131 is a deficient number, since it is larger than the sum of its proper divisors (1).
312010100131 is an equidigital number, since it uses as much as digits as its factorization.
312010100131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 312010100131 its reverse (131001010213), we get a palindrome (443011110344).
The spelling of 312010100131 in words is "three hundred twelve billion, ten million, one hundred thousand, one hundred thirty-one".
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