Base | Representation |
---|---|
bin | 1001000101001010101… |
… | …00011000111111000011 |
3 | 1002211100121011210100212 |
4 | 10202211110120333003 |
5 | 20102444333344141 |
6 | 355200323304335 |
7 | 31353633464123 |
oct | 4424524307703 |
9 | 1084317153325 |
10 | 312011231171 |
11 | 11036122a032 |
12 | 50577b1b0ab |
13 | 235653c64a3 |
14 | 1115c444c83 |
15 | 81b1dec2eb |
hex | 48a5518fc3 |
312011231171 has 2 divisors, whose sum is σ = 312011231172. Its totient is φ = 312011231170.
The previous prime is 312011231153. The next prime is 312011231177. The reversal of 312011231171 is 171132110213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312011231171 is a prime.
It is not a weakly prime, because it can be changed into another prime (312011231177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156005615585 + 156005615586.
It is an arithmetic number, because the mean of its divisors is an integer number (156005615586).
Almost surely, 2312011231171 is an apocalyptic number.
312011231171 is a deficient number, since it is larger than the sum of its proper divisors (1).
312011231171 is an equidigital number, since it uses as much as digits as its factorization.
312011231171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 23.
Adding to 312011231171 its reverse (171132110213), we get a palindrome (483143341384).
The spelling of 312011231171 in words is "three hundred twelve billion, eleven million, two hundred thirty-one thousand, one hundred seventy-one".
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