312012302011331 has 2 divisors, whose sum is σ = 312012302011332. Its totient is φ = 312012302011330.

The previous prime is 312012302011309. The next prime is 312012302011343. The reversal of 312012302011331 is 133110203210213.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 312012302011331 - 2²² = 312012297817027 is a prime.

It is a super-3 number, since 3×312012302011331³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 312012302011297 and 312012302011306.

It is not a weakly prime, because it can be changed into another prime (312012302011301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156006151005665 + 156006151005666.

It is an arithmetic number, because the mean of its divisors is an integer number (156006151005666).

Almost surely, 2^{312012302011331} is an apocalyptic number.

312012302011331 is a deficient number, since it is larger than the sum of its proper divisors (1).

312012302011331 is an equidigital number, since it uses as much as digits as its factorization.

312012302011331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 312012302011331 its reverse (133110203210213), we get a palindrome (445122505221544).

The spelling of 312012302011331 in words is "three hundred twelve trillion, twelve billion, three hundred two million, eleven thousand, three hundred thirty-one".