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312012431998 = 2156006215999
BaseRepresentation
bin1001000101001010110…
…00111110001001111110
31002211100200102210120221
410202211120332021332
520103000140310443
6355200405131554
731353646625101
oct4424530761176
91084320383527
10312012431998
1111036197a253
12505783b9bba
1323565726c37
141115c678738
1581b2087eed
hex48a563e27e

312012431998 has 4 divisors (see below), whose sum is σ = 468018648000. Its totient is φ = 156006215998.

The previous prime is 312012431909. The next prime is 312012432013. The reversal of 312012431998 is 899134210213.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78003107998 + ... + 78003108001.

It is an arithmetic number, because the mean of its divisors is an integer number (117004662000).

Almost surely, 2312012431998 is an apocalyptic number.

312012431998 is a deficient number, since it is larger than the sum of its proper divisors (156006216002).

312012431998 is a wasteful number, since it uses less digits than its factorization.

312012431998 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 156006216001.

The product of its (nonzero) digits is 93312, while the sum is 43.

The spelling of 312012431998 in words is "three hundred twelve billion, twelve million, four hundred thirty-one thousand, nine hundred ninety-eight".

Divisors: 1 2 156006215999 312012431998