Base | Representation |
---|---|
bin | 1001000101001011110… |
… | …10001001000101000101 |
3 | 1002211101021210120120022 |
4 | 10202211322021011011 |
5 | 20103004402034433 |
6 | 355201315344525 |
7 | 31354113552305 |
oct | 4424572110505 |
9 | 1084337716508 |
10 | 312021127493 |
11 | 110366879309 |
12 | 5057b2b2145 |
13 | 2356747caba |
14 | 1115d89d605 |
15 | 81b2c04698 |
hex | 48a5e89145 |
312021127493 has 2 divisors, whose sum is σ = 312021127494. Its totient is φ = 312021127492.
The previous prime is 312021127469. The next prime is 312021127501. The reversal of 312021127493 is 394721120213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 199502475649 + 112518651844 = 446657^2 + 335438^2 .
It is a cyclic number.
It is not a de Polignac number, because 312021127493 - 212 = 312021123397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312021127403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156010563746 + 156010563747.
It is an arithmetic number, because the mean of its divisors is an integer number (156010563747).
Almost surely, 2312021127493 is an apocalyptic number.
It is an amenable number.
312021127493 is a deficient number, since it is larger than the sum of its proper divisors (1).
312021127493 is an equidigital number, since it uses as much as digits as its factorization.
312021127493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 35.
The spelling of 312021127493 in words is "three hundred twelve billion, twenty-one million, one hundred twenty-seven thousand, four hundred ninety-three".
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