Base | Representation |
---|---|
bin | 1110001100000110100001… |
… | …00000001100110100111111 |
3 | 11002110220011211012120122002 |
4 | 13012003100200030310333 |
5 | 13042203440434241343 |
6 | 150210022051012515 |
7 | 6400165062364262 |
oct | 706032040146477 |
9 | 132426154176562 |
10 | 31202140540223 |
11 | 9a3a831995754 |
12 | 35bb22589a13b |
13 | 145447033a4b3 |
14 | 79c297cb4cd9 |
15 | 39198c8888b8 |
hex | 1c60d080cd3f |
31202140540223 has 4 divisors (see below), whose sum is σ = 31440324819288. Its totient is φ = 30963956261160.
The previous prime is 31202140540183. The next prime is 31202140540229. The reversal of 31202140540223 is 32204504120213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31202140540223 - 244 = 13609954495807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31202140540229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119092139336 + ... + 119092139597.
It is an arithmetic number, because the mean of its divisors is an integer number (7860081204822).
Almost surely, 231202140540223 is an apocalyptic number.
31202140540223 is a deficient number, since it is larger than the sum of its proper divisors (238184279065).
31202140540223 is a wasteful number, since it uses less digits than its factorization.
31202140540223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 238184279064.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 31202140540223 its reverse (32204504120213), we get a palindrome (63406644660436).
The spelling of 31202140540223 in words is "thirty-one trillion, two hundred two billion, one hundred forty million, five hundred forty thousand, two hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.088 sec. • engine limits •