Base | Representation |
---|---|
bin | 100011011110010000010011… |
… | …0100000010101011101000111 |
3 | 1111220202221211221121010010201 |
4 | 1012330200212200111131013 |
5 | 311344124342103134003 |
6 | 3023340355520231331 |
7 | 122502542624553142 |
oct | 10674404640253507 |
9 | 1456687757533121 |
10 | 312021430130503 |
11 | 904685aaa21585 |
12 | 2abb3a1576b547 |
13 | 1051465786a2a2 |
14 | 5709cbc613059 |
15 | 26115d7d42b1d |
hex | 11bc826815747 |
312021430130503 has 2 divisors, whose sum is σ = 312021430130504. Its totient is φ = 312021430130502.
The previous prime is 312021430130413. The next prime is 312021430130533. The reversal of 312021430130503 is 305031034120213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312021430130503 is a prime.
It is a super-2 number, since 2×3120214301305032 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312021430130533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156010715065251 + 156010715065252.
It is an arithmetic number, because the mean of its divisors is an integer number (156010715065252).
Almost surely, 2312021430130503 is an apocalyptic number.
312021430130503 is a deficient number, since it is larger than the sum of its proper divisors (1).
312021430130503 is an equidigital number, since it uses as much as digits as its factorization.
312021430130503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 312021430130503 its reverse (305031034120213), we get a palindrome (617052464250716).
The spelling of 312021430130503 in words is "three hundred twelve trillion, twenty-one billion, four hundred thirty million, one hundred thirty thousand, five hundred three".
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