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31202212979149 is a prime number
BaseRepresentation
bin1110001100000110101001…
…10100100010000111001101
311002110220100212111212011021
413012003110310202013031
513042204113010313044
6150210033155354141
76400166632166422
oct706032464420715
9132426325455137
1031202212979149
119a3a869872133
1235bb245bb2951
131454482351174
1479c2a376dd49
15391993de6e84
hex1c60d4d221cd

31202212979149 has 2 divisors, whose sum is σ = 31202212979150. Its totient is φ = 31202212979148.

The previous prime is 31202212979123. The next prime is 31202212979243. The reversal of 31202212979149 is 94197921220213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16684627041124 + 14517585938025 = 4084682^2 + 3810195^2 .

It is a cyclic number.

It is not a de Polignac number, because 31202212979149 - 239 = 30652457165261 is a prime.

It is a super-3 number, since 3×312022129791493 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31202212979096 and 31202212979105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31202212979449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601106489574 + 15601106489575.

It is an arithmetic number, because the mean of its divisors is an integer number (15601106489575).

Almost surely, 231202212979149 is an apocalyptic number.

It is an amenable number.

31202212979149 is a deficient number, since it is larger than the sum of its proper divisors (1).

31202212979149 is an equidigital number, since it uses as much as digits as its factorization.

31202212979149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 979776, while the sum is 52.

The spelling of 31202212979149 in words is "thirty-one trillion, two hundred two billion, two hundred twelve million, nine hundred seventy-nine thousand, one hundred forty-nine".