Base | Representation |
---|---|
bin | 1110001100001000101011… |
… | …01011100000001101011111 |
3 | 11002111000011201001201000111 |
4 | 13012010111223200031133 |
5 | 13042213330042143403 |
6 | 150210333150310451 |
7 | 6400235614265203 |
oct | 706042553401537 |
9 | 132430151051014 |
10 | 31203301131103 |
11 | 9a40278024872 |
12 | 35bb4aa4b8427 |
13 | 14545c691406a |
14 | 79c3680a6b03 |
15 | 391a096dc56d |
hex | 1c6115ae035f |
31203301131103 has 4 divisors (see below), whose sum is σ = 31226127248880. Its totient is φ = 31180475013328.
The previous prime is 31203301131091. The next prime is 31203301131113. The reversal of 31203301131103 is 30113110330213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31203301131103 - 25 = 31203301131071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31203301131113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11413056838 + ... + 11413059571.
It is an arithmetic number, because the mean of its divisors is an integer number (7806531812220).
Almost surely, 231203301131103 is an apocalyptic number.
31203301131103 is a deficient number, since it is larger than the sum of its proper divisors (22826117777).
31203301131103 is a wasteful number, since it uses less digits than its factorization.
31203301131103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22826117776.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 31203301131103 its reverse (30113110330213), we get a palindrome (61316411461316).
The spelling of 31203301131103 in words is "thirty-one trillion, two hundred three billion, three hundred one million, one hundred thirty-one thousand, one hundred three".
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