Base | Representation |
---|---|
bin | 100011011110011000111110… |
… | …0000011111111100000000111 |
3 | 1111220211201220021112022101102 |
4 | 1012330301330003333200013 |
5 | 311344431003111112221 |
6 | 3023353115022250315 |
7 | 122504102134044011 |
oct | 10674617403774007 |
9 | 1456751807468342 |
10 | 312040045410311 |
11 | 90475492848849 |
12 | 2abb754ba2699b |
13 | 105163333b625a |
14 | 570ab66a431b1 |
15 | 2611d2723630b |
hex | 11bcc7c0ff807 |
312040045410311 has 2 divisors, whose sum is σ = 312040045410312. Its totient is φ = 312040045410310.
The previous prime is 312040045410253. The next prime is 312040045410341. The reversal of 312040045410311 is 113014540040213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312040045410311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312040045410341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156020022705155 + 156020022705156.
It is an arithmetic number, because the mean of its divisors is an integer number (156020022705156).
Almost surely, 2312040045410311 is an apocalyptic number.
312040045410311 is a deficient number, since it is larger than the sum of its proper divisors (1).
312040045410311 is an equidigital number, since it uses as much as digits as its factorization.
312040045410311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 312040045410311 its reverse (113014540040213), we get a palindrome (425054585450524).
The spelling of 312040045410311 in words is "three hundred twelve trillion, forty billion, forty-five million, four hundred ten thousand, three hundred eleven".
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