312100230113 has 4 divisors (see below), whose sum is σ = 356685977280. Its totient is φ = 267514482948.

The previous prime is 312100230103. The next prime is 312100230149. The reversal of 312100230113 is 311032001213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311032001213 = 19 ⋅16370105327.

It is a cyclic number.

It is not a de Polignac number, because 312100230113 - 2¹² = 312100226017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 312100230091 and 312100230100.

It is not an unprimeable number, because it can be changed into a prime (312100230103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22292873573 + ... + 22292873586.

It is an arithmetic number, because the mean of its divisors is an integer number (89171494320).

Almost surely, 2^312100230113 is an apocalyptic number.

It is an amenable number.

312100230113 is a deficient number, since it is larger than the sum of its proper divisors (44585747167).

312100230113 is an equidigital number, since it uses as much as digits as its factorization.

312100230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44585747166.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 312100230113 its reverse (311032001213), we get a palindrome (623132231326).

The spelling of 312100230113 in words is "three hundred twelve billion, one hundred million, two hundred thirty thousand, one hundred thirteen".