Base | Representation |
---|---|
bin | 1001000101010101010… |
… | …11001101111001010101 |
3 | 1002211120212021122210021 |
4 | 10202222223031321111 |
5 | 20103140340214031 |
6 | 355213253425141 |
7 | 31356104405524 |
oct | 4425253157125 |
9 | 1084525248707 |
10 | 312101101141 |
11 | 1103a7a31735 |
12 | 505a203b1b1 |
13 | 2357ac0119b |
14 | 1116a35a4bb |
15 | 81b9c50511 |
hex | 48aaacde55 |
312101101141 has 2 divisors, whose sum is σ = 312101101142. Its totient is φ = 312101101140.
The previous prime is 312101101129. The next prime is 312101101181. The reversal of 312101101141 is 141101101213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 311861934916 + 239166225 = 558446^2 + 15465^2 .
It is an emirp because it is prime and its reverse (141101101213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 312101101141 - 213 = 312101092949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312101101181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156050550570 + 156050550571.
It is an arithmetic number, because the mean of its divisors is an integer number (156050550571).
Almost surely, 2312101101141 is an apocalyptic number.
It is an amenable number.
312101101141 is a deficient number, since it is larger than the sum of its proper divisors (1).
312101101141 is an equidigital number, since it uses as much as digits as its factorization.
312101101141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 312101101141 its reverse (141101101213), we get a palindrome (453202202354).
The spelling of 312101101141 in words is "three hundred twelve billion, one hundred one million, one hundred one thousand, one hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •