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31210114211300 = 2252312101142113
BaseRepresentation
bin1110001100010101010111…
…10001010101110111100100
311002111122202112002001001002
413012022223301111313210
513042321303214230200
6150213421210252432
76400566503435603
oct706125361256744
9132448675061032
1031210114211300
119a4315390a862
123600890127118
13145514129256b
1479c812c87a3a
15391ca78d2bd5
hex1c62abc55de4

31210114211300 has 18 divisors (see below), whose sum is σ = 67725947838738. Its totient is φ = 12484045684480.

The previous prime is 31210114211261. The next prime is 31210114211333. The reversal of 31210114211300 is 311241101213.

It can be written as a sum of positive squares in 3 ways, for example, as 86680781056 + 31123433430244 = 294416^2 + 5578838^2 .

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 156050570957 + ... + 156050571156.

Almost surely, 231210114211300 is an apocalyptic number.

It is an amenable number.

31210114211300 is an abundant number, since it is smaller than the sum of its proper divisors (36515833627438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31210114211300 is a wasteful number, since it uses less digits than its factorization.

31210114211300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 312101142127 (or 312101142120 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 31210114211300 its reverse (311241101213), we get a palindrome (31521355312513).

The spelling of 31210114211300 in words is "thirty-one trillion, two hundred ten billion, one hundred fourteen million, two hundred eleven thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 312101142113 624202284226 1248404568452 1560505710565 3121011421130 6242022842260 7802528552825 15605057105650 31210114211300