Base | Representation |
---|---|
bin | 100011011110110101111000… |
… | …0001011100101111110110101 |
3 | 1111221001200010120122210111121 |
4 | 1012331223300023211332311 |
5 | 311401440122003232013 |
6 | 3023441422550503541 |
7 | 122511430362524200 |
oct | 10675536013457665 |
9 | 1457050116583447 |
10 | 312102123102133 |
11 | 90499849007491 |
12 | 2b007595664bb1 |
13 | 1051c147420390 |
14 | 570db75416937 |
15 | 261375c09658d |
hex | 11bdaf02e5fb5 |
312102123102133 has 48 divisors (see below), whose sum is σ = 391272905766960. Its totient is φ = 246756198334464.
The previous prime is 312102123102127. The next prime is 312102123102199. The reversal of 312102123102133 is 331201321201213.
It can be written as a sum of positive squares in 8 ways, for example, as 45060703776529 + 267041419325604 = 6712727^2 + 16341402^2 .
It is a de Polignac number, because none of the positive numbers 2k-312102123102133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 312102123102098 and 312102123102107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312102123102103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10758788733 + ... + 10758817741.
It is an arithmetic number, because the mean of its divisors is an integer number (8151518870145).
Almost surely, 2312102123102133 is an apocalyptic number.
It is an amenable number.
312102123102133 is a deficient number, since it is larger than the sum of its proper divisors (79170782664827).
312102123102133 is a wasteful number, since it uses less digits than its factorization.
312102123102133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40886 (or 40879 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 312102123102133 its reverse (331201321201213), we get a palindrome (643303444303346).
The spelling of 312102123102133 in words is "three hundred twelve trillion, one hundred two billion, one hundred twenty-three million, one hundred two thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •