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31210343244142 = 215605171622071
BaseRepresentation
bin1110001100010101110010…
…11011000010000101101110
311002111200100111001010000221
413012022321123002011232
513042322240332303032
6150213500031241554
76400605254253046
oct706127133020556
9132450314033027
1031210343244142
119a432611225a7
1236009349792ba
13145517987355a
1479c835466726
15391cbca74597
hex1c62b96c216e

31210343244142 has 4 divisors (see below), whose sum is σ = 46815514866216. Its totient is φ = 15605171622070.

The previous prime is 31210343244089. The next prime is 31210343244169. The reversal of 31210343244142 is 24144234301213.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 31210343244098 and 31210343244107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7802585811034 + ... + 7802585811037.

It is an arithmetic number, because the mean of its divisors is an integer number (11703878716554).

Almost surely, 231210343244142 is an apocalyptic number.

31210343244142 is a deficient number, since it is larger than the sum of its proper divisors (15605171622074).

31210343244142 is a wasteful number, since it uses less digits than its factorization.

31210343244142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15605171622073.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 31210343244142 its reverse (24144234301213), we get a palindrome (55354577545355).

The spelling of 31210343244142 in words is "thirty-one trillion, two hundred ten billion, three hundred forty-three million, two hundred forty-four thousand, one hundred forty-two".

Divisors: 1 2 15605171622071 31210343244142