Base | Representation |
---|---|
bin | 11101000100010010… |
… | …001111110001000011 |
3 | 2222120002212211210101 |
4 | 131010102033301003 |
5 | 1002404330424211 |
6 | 22200551143231 |
7 | 2153265031126 |
oct | 350422176103 |
9 | 88502784711 |
10 | 31210404931 |
11 | 12266507192 |
12 | 6070374b17 |
13 | 2c35090534 |
14 | 17210c63bd |
15 | c2a01c5c1 |
hex | 74448fc43 |
31210404931 has 2 divisors, whose sum is σ = 31210404932. Its totient is φ = 31210404930.
The previous prime is 31210404919. The next prime is 31210404959. The reversal of 31210404931 is 13940401213.
It is an a-pointer prime, because the next prime (31210404959) can be obtained adding 31210404931 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31210404931 - 217 = 31210273859 is a prime.
It is a super-2 number, since 2×312104049312 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 31210404931.
It is not a weakly prime, because it can be changed into another prime (31210404031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605202465 + 15605202466.
It is an arithmetic number, because the mean of its divisors is an integer number (15605202466).
Almost surely, 231210404931 is an apocalyptic number.
31210404931 is a deficient number, since it is larger than the sum of its proper divisors (1).
31210404931 is an equidigital number, since it uses as much as digits as its factorization.
31210404931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 28.
The spelling of 31210404931 in words is "thirty-one billion, two hundred ten million, four hundred four thousand, nine hundred thirty-one".
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