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312106843445053 is a prime number
BaseRepresentation
bin100011011110111000000100…
…1100010010001011100111101
31111221002010022112211001200011
41012331300021202101130331
5311402024303410220203
63023443523212103221
7122511655351006666
oct10675601142213475
91457063275731604
10312106843445053
11904a0850574a38
122b008492464b11
131051c71a3546b7
1457100a22bc36d
1526139366ab76d
hex11bdc0989173d

312106843445053 has 2 divisors, whose sum is σ = 312106843445054. Its totient is φ = 312106843445052.

The previous prime is 312106843444987. The next prime is 312106843445057. The reversal of 312106843445053 is 350544348601213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 309976799520964 + 2130043924089 = 17606158^2 + 1459467^2 .

It is a cyclic number.

It is not a de Polignac number, because 312106843445053 - 221 = 312106841347901 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 312106843444988 and 312106843445006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312106843445057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156053421722526 + 156053421722527.

It is an arithmetic number, because the mean of its divisors is an integer number (156053421722527).

Almost surely, 2312106843445053 is an apocalyptic number.

It is an amenable number.

312106843445053 is a deficient number, since it is larger than the sum of its proper divisors (1).

312106843445053 is an equidigital number, since it uses as much as digits as its factorization.

312106843445053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4147200, while the sum is 49.

The spelling of 312106843445053 in words is "three hundred twelve trillion, one hundred six billion, eight hundred forty-three million, four hundred forty-five thousand, fifty-three".