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3121100113 = 19414006547
BaseRepresentation
bin1011101000001000…
…0011010101010001
322001111220022110111
42322002003111101
522343000200423
61233412001321
7140225625145
oct27202032521
98044808414
103121100113
11136186378a
12731300241
133a9805101
1421872b225
1513401560d
hexba083551

3121100113 has 8 divisors (see below), whose sum is σ = 3365500320. Its totient is φ = 2884713120.

The previous prime is 3121100111. The next prime is 3121100117. The reversal of 3121100113 is 3110011213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3121100113 - 21 = 3121100111 is a prime.

It is a super-2 number, since 2×31211001132 = 19482531830737225538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3121100093 and 3121100102.

It is not an unprimeable number, because it can be changed into a prime (3121100111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2002495 + ... + 2004052.

It is an arithmetic number, because the mean of its divisors is an integer number (420687540).

Almost surely, 23121100113 is an apocalyptic number.

It is an amenable number.

3121100113 is a deficient number, since it is larger than the sum of its proper divisors (244400207).

3121100113 is a wasteful number, since it uses less digits than its factorization.

3121100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4006607.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 3121100113 is about 55866.8068981931. The cubic root of 3121100113 is about 1461.4004378687.

Adding to 3121100113 its reverse (3110011213), we get a palindrome (6231111326).

Subtracting from 3121100113 its reverse (3110011213), we obtain a square (11088900 = 33302).

It can be divided in two parts, 3121100 and 113, that added together give a palindrome (3121213).

The spelling of 3121100113 in words is "three billion, one hundred twenty-one million, one hundred thousand, one hundred thirteen".

Divisors: 1 19 41 779 4006547 76124393 164268427 3121100113