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31211032013053 is a prime number
BaseRepresentation
bin1110001100010111000100…
…11110011110100011111101
311002111202010111002012100121
413012023202132132203331
513042330143143404203
6150214052234054541
76400631316556504
oct706134236364375
9132452114065317
1031211032013053
119a435849a0902
123600aa757a451
13145525947c919
1479c89cb1983b
15391d0d2790bd
hex1c62e279e8fd

31211032013053 has 2 divisors, whose sum is σ = 31211032013054. Its totient is φ = 31211032013052.

The previous prime is 31211032013011. The next prime is 31211032013059. The reversal of 31211032013053 is 35031023011213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22537170612889 + 8673861400164 = 4747333^2 + 2945142^2 .

It is an emirp because it is prime and its reverse (35031023011213) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31211032013053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31211032013059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605516006526 + 15605516006527.

It is an arithmetic number, because the mean of its divisors is an integer number (15605516006527).

Almost surely, 231211032013053 is an apocalyptic number.

It is an amenable number.

31211032013053 is a deficient number, since it is larger than the sum of its proper divisors (1).

31211032013053 is an equidigital number, since it uses as much as digits as its factorization.

31211032013053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 31211032013053 its reverse (35031023011213), we get a palindrome (66242055024266).

The spelling of 31211032013053 in words is "thirty-one trillion, two hundred eleven billion, thirty-two million, thirteen thousand, fifty-three".