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31211103113120 = 25575913134910331
BaseRepresentation
bin1110001100010111001101…
…01101101100111110100000
311002111202022102212110022102
413012023212231230332200
513042330314344104440
6150214103254025532
76400633142114360
oct706134655547640
9132452272773272
1031211103113120
119a43611043397
123600b073482a8
13145526b115078
1479c8a83469a0
15391d14620b15
hex1c62e6b6cfa0

31211103113120 has 384 divisors, whose sum is σ = 86608279296000. Its totient is φ = 10408355942400.

The previous prime is 31211103113107. The next prime is 31211103113123. The reversal of 31211103113120 is 2131130111213.

It is a super-2 number, since 2×312111031131202 (a number of 28 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 31211103113092 and 31211103113101.

It is not an unprimeable number, because it can be changed into a prime (31211103113123) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3021106355 + ... + 3021116685.

It is an arithmetic number, because the mean of its divisors is an integer number (225542394000).

Almost surely, 231211103113120 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31211103113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (43304139648000).

31211103113120 is an abundant number, since it is smaller than the sum of its proper divisors (55397176182880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31211103113120 is a wasteful number, since it uses less digits than its factorization.

31211103113120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10892 (or 10884 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 31211103113120 its reverse (2131130111213), we get a palindrome (33342233224333).

The spelling of 31211103113120 in words is "thirty-one trillion, two hundred eleven billion, one hundred three million, one hundred thirteen thousand, one hundred twenty".