Base | Representation |
---|---|
bin | 1110001100010111011010… |
… | …01101100000000100000010 |
3 | 11002111202121000222011211210 |
4 | 13012023231031200010002 |
5 | 13042331030300042010 |
6 | 150214122150150550 |
7 | 6400635634436631 |
oct | 706135515400402 |
9 | 132452530864753 |
10 | 31211212112130 |
11 | 9a43667620a16 |
12 | 3600b37952456 |
13 | 145528788991b |
14 | 79c8b89db518 |
15 | 391d1dea1b20 |
hex | 1c62ed360102 |
31211212112130 has 32 divisors (see below), whose sum is σ = 75283325712000. Its totient is φ = 8281165825152.
The previous prime is 31211212112111. The next prime is 31211212112159. The reversal of 31211212112130 is 3121121211213.
It is a junction number, because it is equal to n+sod(n) for n = 31211212112097 and 31211212112106.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2613998395 + ... + 2614010334.
It is an arithmetic number, because the mean of its divisors is an integer number (2352603928500).
Almost surely, 231211212112130 is an apocalyptic number.
31211212112130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
31211212112130 is an abundant number, since it is smaller than the sum of its proper divisors (44072113599870).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31211212112130 is a wasteful number, since it uses less digits than its factorization.
31211212112130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5228008938.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 31211212112130 its reverse (3121121211213), we get a palindrome (34332333323343).
The spelling of 31211212112130 in words is "thirty-one trillion, two hundred eleven billion, two hundred twelve million, one hundred twelve thousand, one hundred thirty".
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