Base | Representation |
---|---|
bin | 101101011010110001011… |
… | …011010111111011000011 |
3 | 102001101011102120012100021 |
4 | 231122301123113323003 |
5 | 402114024442000003 |
6 | 10345454001434311 |
7 | 441331223525011 |
oct | 55326133277303 |
9 | 12041142505307 |
10 | 3121123000003 |
11 | aa372a625378 |
12 | 424a8993b997 |
13 | 19842258b9c8 |
14 | ab0c54478b1 |
15 | 562c30c52bd |
hex | 2d6b16d7ec3 |
3121123000003 has 2 divisors, whose sum is σ = 3121123000004. Its totient is φ = 3121123000002.
The previous prime is 3121122999961. The next prime is 3121123000019. The reversal of 3121123000003 is 3000003211213.
It is an a-pointer prime, because the next prime (3121123000019) can be obtained adding 3121123000003 to its sum of digits (16).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3121123000003 - 225 = 3121089445571 is a prime.
It is a super-2 number, since 2×31211230000032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3121123000903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560561500001 + 1560561500002.
It is an arithmetic number, because the mean of its divisors is an integer number (1560561500002).
Almost surely, 23121123000003 is an apocalyptic number.
3121123000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121123000003 is an equidigital number, since it uses as much as digits as its factorization.
3121123000003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 3121123000003 its reverse (3000003211213), we get a palindrome (6121126211216).
The spelling of 3121123000003 in words is "three trillion, one hundred twenty-one billion, one hundred twenty-three million, three", and thus it is an aban number.
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