31211310000001 has 4 divisors (see below), whose sum is σ = 31211534379312. Its totient is φ = 31211085620692.

The previous prime is 31211309999981. The next prime is 31211310000011. The reversal of 31211310000001 is 10000001311213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31211310000001 - 2¹⁷ = 31211309868929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31211310000011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111980875 + ... + 112259248.

It is an arithmetic number, because the mean of its divisors is an integer number (7802883594828).

Almost surely, 2^{31211310000001} is an apocalyptic number.

It is an amenable number.

31211310000001 is a deficient number, since it is larger than the sum of its proper divisors (224379311).

31211310000001 is a wasteful number, since it uses less digits than its factorization.

31211310000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224379310.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 31211310000001 its reverse (10000001311213), we get a palindrome (41211311311214).

The spelling of 31211310000001 in words is "thirty-one trillion, two hundred eleven billion, three hundred ten million, one", and thus it is an aban number.