3121131113 has 4 divisors (see below), whose sum is σ = 3123181968. Its totient is φ = 3119080260.

The previous prime is 3121131107. The next prime is 3121131127. The reversal of 3121131113 is 3111311213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3111311213 = 25121 ⋅123853.

It is a cyclic number.

It is not a de Polignac number, because 3121131113 - 2¹⁸ = 3120868969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3121131091 and 3121131100.

It is not an unprimeable number, because it can be changed into a prime (3121131163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1023143 + ... + 1026188.

It is an arithmetic number, because the mean of its divisors is an integer number (780795492).

Almost surely, 2^3121131113 is an apocalyptic number.

It is an amenable number.

3121131113 is a deficient number, since it is larger than the sum of its proper divisors (2050855).

3121131113 is a wasteful number, since it uses less digits than its factorization.

3121131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2050854.

The product of its digits is 54, while the sum is 17.

The square root of 3121131113 is about 55867.0843431085. The cubic root of 3121131113 is about 1461.4052762549.

Adding to 3121131113 its reverse (3111311213), we get a palindrome (6232442326).

The spelling of 3121131113 in words is "three billion, one hundred twenty-one million, one hundred thirty-one thousand, one hundred thirteen".