Base | Representation |
---|---|
bin | 1001000101010110110… |
… | …01110000111010110111 |
3 | 1002211121201020120220020 |
4 | 10202223121300322313 |
5 | 20103202001200343 |
6 | 355214411140223 |
7 | 31356313206231 |
oct | 4425331607267 |
9 | 1084551216806 |
10 | 312113303223 |
11 | 1104039062a7 |
12 | 505a6144673 |
13 | 235805b4157 |
14 | 1116bc15251 |
15 | 81bad60b83 |
hex | 48ab670eb7 |
312113303223 has 4 divisors (see below), whose sum is σ = 416151070968. Its totient is φ = 208075535480.
The previous prime is 312113303189. The next prime is 312113303251. The reversal of 312113303223 is 322303311213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 312113303223 - 28 = 312113302967 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 312113303193 and 312113303202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312113303273) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52018883868 + ... + 52018883873.
It is an arithmetic number, because the mean of its divisors is an integer number (104037767742).
Almost surely, 2312113303223 is an apocalyptic number.
312113303223 is a deficient number, since it is larger than the sum of its proper divisors (104037767745).
312113303223 is a wasteful number, since it uses less digits than its factorization.
312113303223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104037767744.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 312113303223 its reverse (322303311213), we get a palindrome (634416614436).
The spelling of 312113303223 in words is "three hundred twelve billion, one hundred thirteen million, three hundred three thousand, two hundred twenty-three".
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